mger
A) (2+√2)³=(2+√2)(2+√2)(2+√2)=(4+4√2+2)(2+√2)=(6+4√2)(2+√2)=12+6√2+8√2+8= =20+14√2 b) (√5-1)³=(√5-1)(√5-1)(√5-1)=(5-√5-√5+1)(√5-1)=(6-√10)(√5-1)=6√5-6-√50-√10 c) (1+2√5)³=(1+2√5)(1+2√5)(1+2√5)=(1+2√5+2√5+20)(1+2√5)= (1+4√5+20)(1+2√5)=1+2√5+4√5+40+20+40√5=61+46√5
=20+14√2
b) (√5-1)³=(√5-1)(√5-1)(√5-1)=(5-√5-√5+1)(√5-1)=(6-√10)(√5-1)=6√5-6-√50-√10
c) (1+2√5)³=(1+2√5)(1+2√5)(1+2√5)=(1+2√5+2√5+20)(1+2√5)=
(1+4√5+20)(1+2√5)=1+2√5+4√5+40+20+40√5=61+46√5