Odpowiedź:
Zad1
P=
a) P= ==27
b) P= 30
c) P= 28
Zad2
x-dlugosc podstawy trojkata
3+x=11 |-3
x=8
P= 44
Zad3
P==26
Zad4
h=6cm
P= == 42
Wysokosc trapezu wynosi 6cm a jego pole jest równe 42
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Odpowiedź:
Zad1
P=![\frac{a*h}{2} \frac{a*h}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%2Ah%7D%7B2%7D)
a) P=
=
=27![cm^{2} cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
b) P=
30![cm^{2} cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
c) P=
28![cm^{2} cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
Zad2
x-dlugosc podstawy trojkata
3+x=11 |-3
x=8
P=
44![cm^{2} cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
Zad3
P=![\frac{(a+b)*h}{2} \frac{(a+b)*h}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%28a%2Bb%29%2Ah%7D%7B2%7D)
P=![\frac{(10+3)*4}{2} = \frac{(10+3)*4}{2} =](https://tex.z-dn.net/?f=%5Cfrac%7B%2810%2B3%29%2A4%7D%7B2%7D%20%3D)
=
26![cm^{2} cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
Zad4
h=6cm
P=
=
= 42![cm^{2} cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
Wysokosc trapezu wynosi 6cm a jego pole jest równe 42![cm^{2} cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)