Question

Prosze o rozwiazanie ukladu rownan

{(x+4)*(y-2) = xy + 28
{(x-3)*(y+1) = xy - 45

Answer 1

Xy-2x+4y-8=xy+28
xy+x-3y-3=xy-45

-2x+4y=28-8
x-3y=-45+3

-2x+4y=20
x=3y-42

-2(3y-42)+4y=20

-6y+84+4y=20

-2y=-84+20
-2y=-64/-2
y=32


x=3*32-42
x=96-42
x=54