prosze o rozwiazanie układu równań x+y-3=2x-1 3(x+2)=6(y+1) z klamerka
x+y-3=2x-1
3(x+2)=6(y+1)
x-2x+y=-1+3
3x+6=6y+6
-x+y=2
3x-6y=6-6
y=2+x
3x-6(2+x)=0
3x-12-6x=0
-3x=12/:(-3)
x=-4
y=2+(-4)
y=2-4
y=-2
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x+y-3=2x-1
3(x+2)=6(y+1)
x-2x+y=-1+3
3x+6=6y+6
-x+y=2
3x-6y=6-6
y=2+x
3x-6(2+x)=0
y=2+x
3x-12-6x=0
y=2+x
-3x=12/:(-3)
y=2+x
x=-4
y=2+(-4)
x=-4
y=2-4
x=-4
y=-2
x=-4