Prosze o rozwiazanie TYLKO ZADAN Z GWIAZDKA ktora narysowalem. Malo zadan w zalaczniku ! :) Pozdrawi.... Question from @Siostra121

Siostra121 @Siostra121

November 2018 1 10 Report

Prosze o rozwiazanie TYLKO ZADAN Z GWIAZDKA ktora narysowalem. Malo zadan w zalaczniku ! :) Pozdrawiam :D

luki130193

Zad.7

$(-x^3y^2)^2*(x^2y^3)^-^2=x^6y^4*x^-^4y^-^6=x^2y^-^2$

założenie: $x\neq0$ i $y\neq0$

$\frac{(x^4y^-^3)^3*(x^-^2y)^-^4}{(x^6y):(xy^-^5)^-^2}=\frac{x^1^2y^-^9*x^8y^-^4}{(x^6y):(x^-2y^1^0)}=\frac{x^2^0y^-^1^3}{x^8y^-^9}=x^1^2y^-^4$

Zad.8

$45^2*(0,2*3^-^4-3^4*15^-^2)=45^2*(\frac{2}{10}*3^-^4-3^4*(\frac{1}{15})^2)=45^2*(\frac{1}{5}*3^-^4-\frac{3^4}{15^2})=45^2*(\frac{1}{5}*\frac{1}{3^4}-\frac{3^4}{15^2})=45^2(\frac{1}{5*3^4}-\frac{3^4}{225})=$

$45^2*(\frac{1}{5*3^4}-\frac{3^4}{5*45})=45^2*(\frac{45}{4*45*3^4}-\frac{(3^4)^2}{5*45*3^4})=45^2*(\frac{45}{5*45*3^4}-\frac{3^8}{5*45*3^4})=45^2*\frac{45-3^8}{5*45*3^4}=\frac{45^2(45-3^8)}{5*45*3^4}=\frac{45(45-3^8)}{5*3^4}=\frac{9(45-3^8)}{3^4}=\frac{3^2(45-3^8)}{3^4}=\frac{45-3^8}{3^2}=\frac{3^2(5-3^6)}{3^2}=5-3^6=5-729=-724$

$(6^4*8^2-4*12^4):5^-^7= (162*8*8^2-4*81*4^4):5^-^7=(162*8^3-81*4^5):5^-^7=(162*(2^3)^3-81*(2^2)^5):5^-^7=(162*2^9-81*2^1^0):5^-^7=(81*2*2^9-81*2^1^0):5^-^7=(81*2^1^0-81*2^1^0):5^-^7=0:5^-^7=0$

Zad.9

$((1\frac{4}{5})^3*(1\frac{1}{2})^-^6):(\frac{5}{8})^-^2=((\frac{9}{5})^3*(\frac{3}{2})^-^6):(\frac{8}{5})^2=(\frac{9^3}{5^3}*(\frac{2}{3})^6):\frac{8^2}{5^2}=(\frac{(3^2)^3}{5^3}*\frac{2^6}{3^6}):\frac{(2^3)^2}{5^2}=(\frac{3^6}{5^3}*\frac{2^6}{3^6}):\frac{2^6}{5^2}=\frac{2^6}{5^3}:\frac{2^6}{5^2}=\frac{2^6}{5^3}*\frac{5^2}{2^6}=\frac{1}{5}$

$(\frac{5}{14})^-^6*(\frac{56}{15})^-^6*(\frac{2}{3})^1^2=(\frac{14}{5})^6*(\frac{15}{56})^6*\frac{2^1^2}{3^1^2}=\frac{14^6*15^6*2^1^2}{5^6*56^6*3^1^2}=\frac{15^6*2^1^2}{5^6*4^6*3^1^2}=\frac{3^6*2^1^2}{4^6*3^1^2}=\frac{3^6*2^1^2}{(2^2)^6*3^1^2}=\frac{3^6*2^1^2}{2^1^2*3^1^2}=3^-^6=729^-^1=\frac{1}{729}$