Prosze o POMOC ;)
Zad 1 Rozwiaz rownania
a)
b)
c)
zatem:
mnożę przez
czyli
lub
czyli:
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a)![4^{2x-1} =1=4^0 4^{2x-1} =1=4^0](https://tex.z-dn.net/?f=4%5E%7B2x-1%7D+%3D1%3D4%5E0+)
b)![x\neq 0 x\neq 0](https://tex.z-dn.net/?f=x%5Cneq+0)
zatem:![x-3 =-2 \frac{x-1}{x} x-3 =-2 \frac{x-1}{x}](https://tex.z-dn.net/?f=x-3+%3D-2+%5Cfrac%7Bx-1%7D%7Bx%7D)
mnożę przez![x x](https://tex.z-dn.net/?f=x)
czyli![x=-1 x=-1](https://tex.z-dn.net/?f=x%3D-1+)
lub![x=-2 x=-2](https://tex.z-dn.net/?f=x%3D-2)
c)![(\frac{2}{9})^{3x-7} =(\frac{9}{2})^{-(3x-7)} (\frac{2}{9})^{3x-7} =(\frac{9}{2})^{-(3x-7)}](https://tex.z-dn.net/?f=%28%5Cfrac%7B2%7D%7B9%7D%29%5E%7B3x-7%7D+%3D%28%5Cfrac%7B9%7D%7B2%7D%29%5E%7B-%283x-7%29%7D+)
zatem:![-3x+7 =7x-3 -3x+7 =7x-3](https://tex.z-dn.net/?f=-3x%2B7+%3D7x-3)
czyli:![x=1 x=1](https://tex.z-dn.net/?f=x%3D1)