Prosze o pomoc dam najj!
zadania w załaczniku
Zad1.
x²+12x+20=0 a=1;b=12;c=20
Δ=b²-4ac
Δ=12²-4*1*20
Δ=144-80=64
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Zad1.
x²+12x+20=0 a=1;b=12;c=20
Δ=b²-4ac
Δ=12²-4*1*20
Δ=144-80=64
√Δ=√64=8x1=-b-√Δ/2*ax1=-12-8/2=-20/2=-10 x2=-b+√Δ/2*ax2=-12+8/2=-4/2=-2 Czyli odpowiedź B