Question

Prosze o pomoc... dam naj..

Answer 1

Log(3) 3 = x
3^x =3
x=1
log(7)1 =x
7^x=1
x=0
log (3) 2^2 -log (3) 5^3 =
log (3)4-log (3) 125= log (3) [4|125]