Question

Prosze o pomc w trudnym dla mnie zadaniu;(

Answer 1

a) (√81 - √64)* √5 i 1/16 =

=(9-8) * √81/16=

=1* 9/4 = 9/4

b) (√1,21 + √3 i 1/16) / (√2,56 - √1 i 9/16)=

= 1,1 +√49/16 / 1,6 - √25/16 =

= 1,1 + 7/4 / 1,6 - 5/4 =

= (11/10 + 7/4) / (16/10- 5/4)=

= (22/20 + 35/20) / (32/20 - 25/20)=

= (57/20)/ (7/20) =

57/20 * 20/7 = 57/7 = 8 i1/7

c) (5√0,09 - 3√0,04)*(2√2i1/4 - 3√1 i 7/9)=

= (5*0,3 - 3*0,2)*(2*3/2 - 3*4/3)=

=(1,5-0,6) * (3-4)=

=0,9* (-1) = -0,9

d) (∛3i3/8 * ∛0,125) / (∛64/ ∛8/27)=

=(∛27/8 *0,5) / (8: 2/3) = 3/2 * 0,5 / (8*3/2)=

= 0,75 / 12 = 0,0625