Proszę o zrobienie tych zadań dodane w załączniku plis :***
α=360°-(120° + 90° + 90°)=60°
β=360°-(110° + 90° + 90°)=70°
γ=360°-(130° + 90° + 90°)=50°
K i W;
L i A;
P i S
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α=360°-(120° + 90° + 90°)=60°
β=360°-(110° + 90° + 90°)=70°
γ=360°-(130° + 90° + 90°)=50°
K i W;
L i A;
P i S