Odpowiedź:
zad 1
a) log₂128 = log₂2⁷ = 7log₂2 = 7 * 1 = 7
b) log₃27 = log₃3³ = 3log₃3 = 3 * 1 = 3
c) log₅1 = 0 ponieważ 5⁰ = 1
d) log₁₎₂0,5 = log₀,₅0,5 = 1
e) log₂(1/16) = log₂(1/2)⁴ = log₂2⁻⁴ = - 4log₂2 = - 4 * 1 = - 4
f) log₃(1/81) = log₃(1/3)⁴ = log₃3⁻⁴ = - 4log₃3 = - 4 * 1 = - 4
g) log₉1 = 0 ponieważ 9⁰ = 1
zad 2
a) log4 + log250 = log(4 * 250) = log1000 = 3 ponieważ 10³ = 1000
b) log₆72 - log₆2 = log₆(72/2) = log₆36 = 2
c) log₇(49/3) + log₇3 = log₇(49/3 * 3) = log₇49 = 7
d) log₈128 - log₈2 = log₈(128/2) = log₈64 = 2
e) log₂8√2 = log₂(2³ * 2¹⁾² ) = log₂2³⁺¹⁾² = log₂2³'⁵ = 3,5
f) log₃(1/√3) = log₃(√3)⁻¹ = log₃(3¹⁾²)⁻¹ = log₃3⁻¹⁾² = - 1/2
zad 3
a) log₃81⁵ = log₃(3⁴)⁵ = log₃3²⁰ = 20log₃3 = 20 * 1 = 20
b) log₂16⁷ = log₂(2⁴)⁷ = log₂2²⁸ = 28log₂2 = 28 * 1 = 28
c) log₅25⁻³ = log₅(5²)⁻³ = log₅5⁻⁶ = - 6log₅5 = - 6 * 1 = - 6
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Odpowiedź:
zad 1
a) log₂128 = log₂2⁷ = 7log₂2 = 7 * 1 = 7
b) log₃27 = log₃3³ = 3log₃3 = 3 * 1 = 3
c) log₅1 = 0 ponieważ 5⁰ = 1
d) log₁₎₂0,5 = log₀,₅0,5 = 1
e) log₂(1/16) = log₂(1/2)⁴ = log₂2⁻⁴ = - 4log₂2 = - 4 * 1 = - 4
f) log₃(1/81) = log₃(1/3)⁴ = log₃3⁻⁴ = - 4log₃3 = - 4 * 1 = - 4
g) log₉1 = 0 ponieważ 9⁰ = 1
zad 2
a) log4 + log250 = log(4 * 250) = log1000 = 3 ponieważ 10³ = 1000
b) log₆72 - log₆2 = log₆(72/2) = log₆36 = 2
c) log₇(49/3) + log₇3 = log₇(49/3 * 3) = log₇49 = 7
d) log₈128 - log₈2 = log₈(128/2) = log₈64 = 2
e) log₂8√2 = log₂(2³ * 2¹⁾² ) = log₂2³⁺¹⁾² = log₂2³'⁵ = 3,5
f) log₃(1/√3) = log₃(√3)⁻¹ = log₃(3¹⁾²)⁻¹ = log₃3⁻¹⁾² = - 1/2
zad 3
a) log₃81⁵ = log₃(3⁴)⁵ = log₃3²⁰ = 20log₃3 = 20 * 1 = 20
b) log₂16⁷ = log₂(2⁴)⁷ = log₂2²⁸ = 28log₂2 = 28 * 1 = 28
c) log₅25⁻³ = log₅(5²)⁻³ = log₅5⁻⁶ = - 6log₅5 = - 6 * 1 = - 6