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w takim wypadku nadtlenek wodoru musi się utlenić do tlenu
H2O2 ----> O2 + 2H(+) + 2e |*3
Cr2O7(2-) + 14H(+) + 6e ----> 2Cr(3+) + 7H2O |*1
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Cr2O7(2-) + 14H(+) + 6e + 3H2O2 ----> 3O2 + 6H(+) + 6e + 2Cr(3+) + 7H2O
po skróceniu i uproszczeniu otrzymamy
3H2O2 + Na2Cr2O7 + 4H2SO4 ---> 3O2 + Na2SO4+Cr2(SO4)3+7H2O