Proszę o szybką odpowiedź.
stąd
11.
¹⁰√x = 2 ¹⁰√3
√y = 10√30
¹⁰√x = 2 ¹⁰√3 I()¹⁰
x = 2¹⁰·3 = 1024·3
x = 3072
√y = 10√30 I()²
y = 10²·30 = 100·30
y = 3000
x-y = 3072-3000
x-y = 72
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stąd
stąd
11.
¹⁰√x = 2 ¹⁰√3
√y = 10√30
¹⁰√x = 2 ¹⁰√3 I()¹⁰
x = 2¹⁰·3 = 1024·3
x = 3072
√y = 10√30 I()²
y = 10²·30 = 100·30
y = 3000
x-y = 3072-3000
x-y = 72
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