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w zad 2 trzeba policzyć deltę
a = 1
b = 5
c = 6
Δ = b²-4ac
Δ = 25-4*1*6
Δ = 25-24
Δ = 1
x1 = -b-√Δ/2a
x2 = -b+√Δ/2a
x1 = -5-1/2 = -6/2 = -3
x2 = -5+1/2 = -4/2 = -2
D = R-{-2, -3}
czyli jest dobrze