Proszę o rozwiązanie zadania 16 i przykładu e) z zadania 15 .
zad 15
e) x+3=4-√7x
x+√7x = 4-3
x(1+√7)=1
x= 1
(1+√7)
zad. 16
a)(x+5)(5-x) = 5x-x^2
5x-x^2+25-5x=5x-x^2
-5x=-25
x=5
b)(√2-x)^2-(x-2√2)^2=6
2-2√2x+x^2-(x^2-4√2x+8)=6
2-2√2x+x^2-x^2+4√2x-8=6
-6+2√2x=6
2√2x=6+6
2√2x=12 /:2
√2x=6
x= 3√2
c) (x+3)(x-3)= x(x+9)-9(x+1)
x^2-9 = x^2+9x-9x-9
0=0
d) (1/2 x+2)(2-1/2x)+(1+1/2x)^2 = 0
4-1/4x^2+(1+x+1/4x^2)=0
5+x=0
x=-5
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zad 15
e) x+3=4-√7x
x+√7x = 4-3
x(1+√7)=1
x= 1
(1+√7)
zad. 16
a)(x+5)(5-x) = 5x-x^2
5x-x^2+25-5x=5x-x^2
-5x=-25
x=5
b)(√2-x)^2-(x-2√2)^2=6
2-2√2x+x^2-(x^2-4√2x+8)=6
2-2√2x+x^2-x^2+4√2x-8=6
-6+2√2x=6
2√2x=6+6
2√2x=12 /:2
√2x=6
x= 3√2
c) (x+3)(x-3)= x(x+9)-9(x+1)
x^2-9 = x^2+9x-9x-9
0=0
d) (1/2 x+2)(2-1/2x)+(1+1/2x)^2 = 0
4-1/4x^2+(1+x+1/4x^2)=0
5+x=0
x=-5