Question

Proszę o rozwiązanie : x^3 - 2x^2 - 3x = 0

Answer 1

X³ - 2x² - 3x = 0
x(x² - 2x - 3) = 0
x = 0  ∨  x² - 2x - 3 = 0
x² - 2x - 3 = 0
Δ = (-2)² - 4 * 1 * (-3) = 4 + 12 = 16
√Δ = 4
x₁ = (2 + 4) / 2 = 3
x₂ = (2 - 4) / 2 = -1
odp. x ∈ {-1;0;3}