Proszę o rozwiązanie układu równań:
x(x+1) - (x+2)² = y - 3
½x - ¼y = 4
a) x(x+1)-(x+2)2=y-3
x2+x-x2+4=y-3
x=y-7
x²+1x-x²+4=y-3
1/2x - 1/4y=4
1x+4=y-3
1/2x-1/4y=4 /2
1x-1/2y=8 /2
1x-y=-3
2x-y=16
3x=13 /:3
x=13/3
x=4 1/3
1x-y= -3
1(4 1/3) - y= -3
13/3 - y=-3
y=-3 - 13/3
y=-3- 4 1/3
y=-7 1/3
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a) x(x+1)-(x+2)2=y-3
x2+x-x2+4=y-3
x=y-7
x(x+1) - (x+2)² = y - 3
½x - ¼y = 4
x²+1x-x²+4=y-3
1/2x - 1/4y=4
1x+4=y-3
1/2x-1/4y=4 /2
1x+4=y-3
1x-1/2y=8 /2
1x-y=-3
2x-y=16
3x=13 /:3
x=13/3
x=4 1/3
1x-y= -3
1(4 1/3) - y= -3
13/3 - y=-3
y=-3 - 13/3
y=-3- 4 1/3
y=-7 1/3