Proszę o rozwiązanie tych zadań :)
oblicz pole powierzchni namiotu
szerokość 2 m długość 2,2m wysokość trojkąta 1,6 m
Pp=2m*2,2m=4,4m^{2}
Pb= (2,2m*1,6m):2=3,52m^{2}:2= 1,76m^{2}
Pc=4,4m^{2}+1,76M^{2}=6,16m^{2}
p=1/2*a*h
p=1*1.6
p=1.6m2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Pp=2m*2,2m=4,4m^{2}
Pb= (2,2m*1,6m):2=3,52m^{2}:2= 1,76m^{2}
Pc=4,4m^{2}+1,76M^{2}=6,16m^{2}
p=1/2*a*h
p=1*1.6
p=1.6m2