Proszę o rozwiązanie ETAPAMI tego przykładu. Wynik to 2x! Daję naj :)
1-[x-[x-(1-x)-(x-1)+x]-(x-1)]
1-[x-[x-(1-x)-(x-1)+x]-(x-1)]=
1-[x-[x-1+x-x+1+x]-(x-1)]=
1-[x-[2x]-(x-1)]=
1-[x-2x-x+1]=
1-[1]=1-1=0
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1-[x-[x-(1-x)-(x-1)+x]-(x-1)]=
1-[x-[x-1+x-x+1+x]-(x-1)]=
1-[x-[2x]-(x-1)]=
1-[x-2x-x+1]=
1-[1]=1-1=0