Question

Proszę o rozwiazanie tylko trzeba zrobić działania i je rozpisac DAM NAJJ:.3\5+2\3=
1i4\5:1i1\2+1\15
2i1\3x3\7+2\3:3i1\3+1\15
3i1\5x3\8
(8i1\6-4i29\30)x3\8
2i2\3x1i1\4:(7i8\21-3\7x11
7\9:5\9
1i2\5:2i1\3+2i1\5x4\11
1i3\4x(3i2\3+4i1\5+1i1\3):1i9\14x1\7
4i1\3-1i3\5
1i1\2+1\6+4\9x2i2\5
(3i1\15-1i3|5)x5-2x3i2\3+13i2\3:5
PS;to jest w pidręczniku matematyka z kluczem kl 5 cz.1 str 114 wszystkie serie

Answer 1

1 4/5 = 9/5
1 1/2 = 3/2
Korzystając z zasady mówiącej, że dzielenie przez ułamek to jak mnożenie przez jego odwrotność obliczamy, że:
9/5*2/3=3/5*2/1=6/5=1 1/5
1 1/5 = 1 3/15
1 3/15 + 1/15 = 1 4/15

2 1/3= 7/3
7/3*3/7=1
3 1/3 = 10/3
2/3:10/3 = 2/3*3/10=1/5
1/5 = 3/15
1 + 3/15 +1/15 = 1 4/15

8 1/6 = 49/6 = 245/30
4 29/30 = 149/30
245/30 + 149/30 = 394/30
394/30*3/8 = 197/10*1/4 = 197/40 = 4 37/40

2 2/3 = 8/3
1 1/4 = 5/4
8/3*5/4 = 10/3 = 3 1/3
3/7*11= 33/7 = 4 5/7 = 4 15/21
7 8/21 = 6 29/21
6 29/21 - 4 15/21 = 2 14/21 = 56/21
10/3:56/21 = 10/3*21/56 = 5*7/28 = 35/28 = 1 7/28 = 1 1/4

7/9:5/9 = 7/9*9/5 = 7/5 = 1 2/5

1 2/5 = 7/5
2 1/3 = 7/3
7/5:7/3 = 7/5*3/7=3/5
2 1/5 = 11/5
11/5*4/11 = 4/5
3/5+4/5 = 7/5 = 1 2/5

1 3/4 = 7/4
3 2/3 + 1 1/3 + 4 1/5 = 9 1/5 = 46/5
7/4*46/5 = 7/2*23/5 = 161/10 = 16 1/10
1 9/14 = 23/14
23/14*1/7= 23/98
161/10:23/98 = 161/10*98/23 = 14/10 = 1 4/10

4 1/3 = 4 5/15 = 3 20/15
1 3/5 = 1 9/15
3 20/15 - 1 9/15 = 2 11/15

3 1/15 = 2 16/15
1 3/5 = 1 9/15
2 16/15 - 1 9/15 = 1 7/15 = 22/15
22/15*5= 22/3
3 2/3 = 11/3
11/3 * 2 = 22/3
13 2/3 = 41/3
41/3:5 = 41/3*1/5 = 41/15
22/3 - 22/3 = 0
0+41/15 = 41/15 = 2 11/15