Question

Proszę o pomoc, daje naj​

Answer 1

Odpowiedź:

zad 7

(√2x + 1)² = 2(x² + x + 1)

2x² + 2√2x + 1 = 2x² + 2x + 2

2x² - 2x² + 2√2x - 2x = 2 - 1

2√2x - 2x =1

x(2√2 - 2) = 1

2x(√2 - 1) = 1

x = 1 : 2(√2 - 1) = (√2 + 1/)/[2(√2 - 1)(√2 + 1)] = (√2 + 1)/[2(2 - 1) = (√2 + 1)/(2 * 1) =

= (√2 + 1)/2 = 1/2(√2 + 1 )

Odp: B