Proszę o jak najszybsze rozwiązanie tych zadań ;D naje najjj :D.... Question from @Patrykstudent

basetla 1.
a) -1/6 < -1/7
b) 1/9 > 0,11
c) 5/4 = 1,25

2.
a) -5(-8-3+7) - (- (-3)) = -5 *(-4) -3 = 20 - 3 = 17

b) -4² - 2:7 * 1/7 = -16 - 2/7 * 1/7 = -16 - 2/49 = -16 ²/₄₉

c)
6/7 - 20/7 *(6/7 - 1,2)² = 6/7 - 20/7 *(6/7 - 6/5)² = 6/7 - 20/7 *(30/35 - 42/35)² =
= 6/7 - 20/7 *(-12/35)² = 6/7 - 20/7 * 144/1225 = 6/7 - 4/7 * 144/245 =
= 6/7 - 576/1715 = 1470/1715 - 576/1715 = 894/1715

$3.\\\\\frac{\sqrt{18}-6\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{9*2}-6\sqrt{2}}{\sqrt{2}} = \frac{3\sqrt{2}-6\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}*(3-6)}{\sqrt{2}} = -3$

$4.\\\\-3x-5=7x-2(3x-1)\\\\-3x-5=7x-6x+2\\\\-3x-5 = x+2\\\\-3x-x=2+5\\\\-4x = 7 \ \ \ \ /:(-4)\\\\x = -\frac{7}{4}\\\\x = -1\frac{3}{4}$

$5.\\\\20\% \ masy \ 40kg = 0,2*40kg = 8 \ kg\\\\10 \ zl \ x\% \ kwoty \ 250 \ zl \ \ to \ 4\% \ \ \ \ (x = \frac{10}{250}*100\% = 4\%)\\\\30 \ m \ stanowi \ 15\% \ drogi \ o \ dlug. \ 200 \ m \ \ \ \ (x = \frac{100\%}{15\%}*30 \ m = 200 \ m)$

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Siemka ;D potrzebuje to zadanie na już ;) nie mogę sobie z tym poradzić daje naj :)

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