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| * (2x-1)
5x+4 = 3*(2x-1)
5x+4 = 6x-3
-x+4=-3
-x = -7 | *(-1)
x=7
2) = 0 | * (x-3) Df: x€R \ {3}
x²-9=0 ⇒ (x-3)(x+3)=0 ⇒ x=3 (nie nalezy do dziedziny) ∨ x=-3 ⇒ 1 rozwiązanie