Question

Proszę o całkowite rozwiązanie, z wszystkimi obliczeniami itp. :)

1. x+1= 2(3x-1)
2. 3x- (2x +3)= 5x
3. 5-2( 3-x)= x-1
4. 2x-1 ≤ x-5
5. 2(x+3)-1 > x-5
6. 3(x-1)-2(2+x) > 1-x

DAJĘ NAJ!!!

Answer 1

1.

x+1= 2(3x-1)

x + 1 = 6x - 2

x - 6x = -2 - 1

-5x = -3

x = 3/5

2.

3x- (2x +3)= 5x

3x - 2x - 3 = 5x

x - 5x = 3

-4x = 3

x = -3/4

3.

5-2( 3-x)= x-1

5 - 6 + 2x = x - 1

2x - x = -1 + 6 - 5

x = 0

4.

2x-1 ≤ x-5

2x - x ≤ -5 + 1

x ≤ -4

5.

2(x+3)-1 > x-5

2x + 6 - 1 > x - 5

2x - x > -5 - 5

x > -10

6.

3(x-1)-2(2+x) > 1-x

3x - 3 - 4 - 2x > 1 - x

x + x > 1 + 7

2x > 8

x > 4

Answer 2

1) x+1=2(3x-1)                      2)3x-(2x+3)=5x                       3)5-2(3-x)=x-1

   

   x+1=6x-2/-6x-1                     3x-2x-3=5x                            5-6+2x=x-1

 

   -5x=-3                                   x-3=5x/-5x+3                        -1+2x=x-1/+1-x 

 

   x=3/5                                    -4x=3                                        x=0

 

                                                x=-3/4 

 

 

4)2x-1 ≤x-5/-x+1                    5)2(x+3)-1 >x-5                       6) 3(x-1)-2(2+x)>1-x

 

   x ≤-4                                     2x+6-1 >x-5/-x-5                      3x-3-4-2x>1-x

 

                                                x >-10                                      x-7>1-x/+x+7

 

                                                                                                 2x>8

 

                                                                                                 x>4