Question

Proszę na jutro Matematyka błagam! dam naj

^potęga

(2x-2)^3

5+3x)^3

(1-y)^3

(3+3x)^3

(1-√2)^3

(2-√3)^3

(4-√5)^3

(√2-2)^3

(√7+√5)^3

2√2-1)^3

(1+3√3)^3

Answer 1

(2x-2)^3=8x^3-24x^2+24x-8
(5+3x)^3=125+225x+135x^2+27x^3
(1-y)^3=1-3y+3y^2-y^3
(3+3x)^3=27+81x+81x^2+27x^3
(1-√2)^3=7-5√2
(2-√3)^3=26-15√3
(4-√5)^3=124-53√5
(√2-2)^3=14√2-20
(√7+√5)^3=22√7+26√5
(2√2-1)^3=(1+√2)^3=7+5√2
(1+3√3)^3=(4+√3)^3=100+51√3