Proces masowy pierwiazdków wchodzących w skład metyloaniony masa atomowa węgla 12u wodoru 1u azotu 14u.
mCH3NH2=12u+5u+14u=31u
%C = (12/31)*100% = 38,7%
%H = (5/31)*100% = 16,1%
%N = (14/31)*100% = 45,2%
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mCH3NH2=12u+5u+14u=31u
%C = (12/31)*100% = 38,7%
%H = (5/31)*100% = 16,1%
%N = (14/31)*100% = 45,2%