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okrąg na rysunku ma średnicę 12, a więc promień to połowa średnicy czyli 12:2=6
2*π*6 = 12π
FAŁSZ
P = 4π
wzór na pole P = πr²
πr² = 4π | :π
r² = 4
r = √4 = 2
FAŁSZ