Question

Potrzebuje pomocy z tych zadań z matematyki bo mam z nich zaliczenie dam naj

Answer 1

1.
r = 2,5 m
P = ?

P = πr² = π × (2,5m)² = 6,25π m²

2.
L = 12π cm²
i
L = 2πr = πd
d = ?

πd = 12π    /:π
d = 12 cm

3.
r = 2
a = 3π
b = 2

P = a × b - 1/4 × πr²
P = 3π × 2 - 1/4 × π × 2² = 6π - 1/4π × 4 = 6π - π = 5π  [j²]

4.
P = 144π m²
P = πr²
L = ?

πr² = 144π    /:π
r² = 144 = 12 × 12
r = 12 m
L = 2πr = 2π × 12m
L = 24π m

5.
d = 12 cm
L = 2πr = πd = 3,14 × 12 cm
L = 37,68 cm
Odp. A

6.
d = 8 cm
L = πd + 2d
L = π × 8cm + 2 × 8cm = (8π + 16) cm