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H2O2 + 2e --->2OH(-) |*4
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2Cr(3+) + 16OH(-) + 4H2O2 + 8e --->8OH(-) + 2CrO4(-) + 8e + 8H2O
po skróceniu
2Cr(3+) + 8OH(-) + 4H2O2 --->2CrO4(-) + 8H2O
po podstawieniu przeciwjonów
Cr2(SO4)3 + 8NaOH + 4H2O2 --->2NaCrO4 + 8H2O + 3Na2SO4