Potęga o wykładniku wymiernym.
a
(V10)^6=V10*V10*V10*V10*V10*V10=1000
b
V(4^10)=(4^10)^1/2=4^(10*1/2)=4^5=1024
c
'3'V(125^2)=125^2/3=5^(3*2/3)=5^2=25
d
'5'V(32^3)=32^3/5=2^(5*3/5)=2^3=8
e
('8'V625)^2=(625^1/8)^2=625^1/4=(5^4)^1/4=5
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a
(V10)^6=V10*V10*V10*V10*V10*V10=1000
b
V(4^10)=(4^10)^1/2=4^(10*1/2)=4^5=1024
c
'3'V(125^2)=125^2/3=5^(3*2/3)=5^2=25
d
'5'V(32^3)=32^3/5=2^(5*3/5)=2^3=8
e
('8'V625)^2=(625^1/8)^2=625^1/4=(5^4)^1/4=5