" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
x³ - 3x² + 3x - 1 = Agrupamos
(x³ - 1) -(3x² - 3x)=1er parentesis tenemos diferencia de cubos x³-y³= (x - y)
(x ² + xy + y²),el 2do parentesis sacamos factor comun 3x
(x - 1)( x² + x + 1) -3x( x - 1) Sacamos factor comun ( x -1)
(x - 1)(x² + x + 1 - 3x) =
( x - 1)( x² -2x + 1)
Respuesta.
x³ - 3x² + 3x - 1 = ( x - 1)(x² - 2x +1)