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Mayor: (X+1)
Del problema:
X/3 +(X+1)/2 = X/5+10
MCM(2;3;5)=30
multiplicando por 30 para eliminar denominadores:
10X +15(X+1)=6X+300
10X+15X-6X=300-15
19X= 285
x= 285/19
x=15
Los números son 15 y 16