por fa resuelve me esto por fis
h(t)=1.2+4t-2t²
h(t)=1.2+4t-2t²
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aplica la ec. 2º grado y
tenemos t=-1,63 y t=-0.367
-b+-V(b^2-4ac) -4+-V( 16-9.6)
------------------------- = --------------------- = t1=-1,63 t2= -0.367
2a 4