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b) 2*(2n+1)=22
c) 12*t+4=100
d) (n+n+1):5=3
c - liczba całkowita
a)
(2x - 2) + (2x) +(2x + 2) = 30
6x = 30
x = 5
b)
2(2n - 1) = 22
2n - 1 = 11
c)
12n + 4 = 100
n = 96/12 = 8
d)
([c] + [c + 1])/5 = 3
(2c + 1)/5 = 3
c = 7
c + 1 = 8
jak masz pytania to pisz na pw
2x 2*5=10 6x+4=30
2x+2 2*5+2=12 6x=30/;6
x=5
b) 22/2 = 11
c) 100-4 = 96
96 / 12 = 8
Bedzie to 8 tuzinow.
d) (x+y);5=3
(7+8) ;5=3 ;)