Pomożecie rozwiązać ? :
-3 (a-2b-c)=
2x(ax-bx) -3a (-x-b) =
2• (x-2) (x-3) =
-3 (a-2b-c)= -3a+6b+3c
2x(ax-bx) -3a (-x-b) =2ax²-2bx²+3ax+3ab
2*(x-2) (x-3) =2(x²-3x-2x+6)=2x²-6x-4x+12=2x²-10x+12
-3(a-2b-c) = -3a+6b+3c
2x(ax-bx)-3a(-x-b) = 2ax²-2bx²+3ax+3ab
2*(x-2)(x-3) = 2(x²-3x-2x+6) = 2x²-6x-4x+12 = 2x²-10x+12
Proszę o naj... :)
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-3 (a-2b-c)= -3a+6b+3c
2x(ax-bx) -3a (-x-b) =2ax²-2bx²+3ax+3ab
2*(x-2) (x-3) =2(x²-3x-2x+6)=2x²-6x-4x+12=2x²-10x+12
-3(a-2b-c) = -3a+6b+3c
2x(ax-bx)-3a(-x-b) = 2ax²-2bx²+3ax+3ab
2*(x-2)(x-3) = 2(x²-3x-2x+6) = 2x²-6x-4x+12 = 2x²-10x+12
Proszę o naj... :)