pomożecie mi :
a )x2= (1-x)(1+x)
B) (X-1)2-1=0
C) (2x+3)2 =(x-3)2
a) x2=1-x2
2x2=1 /2
x2=1/2 /pierwiastek z 2
x = pierwiastek z 1/2
b) x2 - 2x + 1 - 1 = 0 albo 2x - 2 - 1 = 0
x = 0 2x=3 => x=2/3
c) 4x2 + 12x + 9 = x2 - 6x +9 albo 4x + 6 = 2x - 6
3x2 + 18x = 0 2x = - 12 / :2
x = 0 x = -6
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a) x2=1-x2
2x2=1 /2
x2=1/2 /pierwiastek z 2
x = pierwiastek z 1/2
b) x2 - 2x + 1 - 1 = 0 albo 2x - 2 - 1 = 0
x = 0 2x=3 => x=2/3
c) 4x2 + 12x + 9 = x2 - 6x +9 albo 4x + 6 = 2x - 6
3x2 + 18x = 0 2x = - 12 / :2
x = 0 x = -6