Pomoże ktoś z tymi pierwiastkami? Mam straszny problem i maksymalnie nie ogarniam :(.... Question from @mateuszklis23

April 2022 2 16 Report

Pomoże ktoś z tymi pierwiastkami? Mam straszny problem i maksymalnie nie ogarniam :(

konegunda2020

1. $1. \frac{\sqrt{7*18} }{\sqrt{14} } = \frac{\sqrt126}{\sqrt14} =\sqrt{9} = 3\\2. \frac{\sqrt2 * 26}{13} = \frac{\sqrt 52}{\sqrt13} = \sqrt{4} = 2\\3. \frac{\sqrt14*18 }{\sqrt{7} } = \frac{\sqrt252}{\sqrt7} = \sqrt{36} = 6$

4 votes Thanks 1

Magda

Odpowiedź:

$\frac{\sqrt{7}\cdot\sqrt{18}}{\sqrt{14}}=\frac{\sqrt{126}}{\sqrt{14}}=\sqrt{\frac{126}{14}}=\sqrt{9}=3\\\\\\\frac{\sqrt{2}}{\sqrt{13}}\cdot\sqrt{26}=\frac{\sqrt{52}}{\sqrt{13}}=\sqrt{\frac{52}{13}}=\sqrt{4}=2\\\\\\\sqrt{\not14}\cdot\frac{\sqrt{18}}{\sqrt{\not7}}=\sqrt{2}\cdot\sqrt{18}=\sqrt{36}=6$

5 votes Thanks 1

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