pomocy!!!!!!!
oblicz pole i obwod prostokatow o podanych wymiarach>
a-jedna czwarta cm b-2,25cm
p=
o=
a-8cm b-23,45cm
p=
o=
a-0,111cm b-0,2cm
p=
o=
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a= 1/4 cm b = 2,25 cm
p= 0,25 x 2,25 = 0,5625 cm^2
o= 0,25 x 2 + 2,25 x 2 = 5 cm
a=8 b = 23,45
p= 8 x 23,45= 187,6 cm^2
o= 8 x 2 + 23,45 x 2=62,9 cm
a=0,111 b = 0,2
p=0,111x 0,2=0,0222 cm^2
o=0,111 x 2 + 0,2 x 2=0,622 cm
2,25 = 2 1/4
p = 2 1/4 * 1/4 = 1 1/8cm 2
o= 1/4 * 2 + 2 1/4 * 2 = 5
p = 8 * 23, 45 = 187,6cm 2
o = 8 * 2 + 23,45 * 2 = 62,9
p= 0,111 * 0,2 = 0,0222cm 2
o= 0,111 * 2 + 0,2 * 2 = 0,622