Pomocy !!!
Pozdrawiam.
3(x²-2x+1) - (x²-5) ≥ 3x² - (x² - 16)
3x² - 6x + 3 - x² + 5 ≥ 3x² - x² + 16
2x² - 6x + 8 ≥ 2x² + 16
2x² - 2x² - 6x ≥ 16 - 8
-6x ≥ 8 /:(-6)
x ≤ -8/6
x ≤ -4/3
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Pozdrawiam.
3(x²-2x+1) - (x²-5) ≥ 3x² - (x² - 16)
3x² - 6x + 3 - x² + 5 ≥ 3x² - x² + 16
2x² - 6x + 8 ≥ 2x² + 16
2x² - 2x² - 6x ≥ 16 - 8
-6x ≥ 8 /:(-6)
x ≤ -8/6
x ≤ -4/3