Pomocy! zad 2 str 92 matematyka klasa 1 gimnazjum.
Doprowadż do najprostszej postaći.
interesuje mnie to rozwinięcie zadania nie wyniki .
2(a-4b+c)-5(3a+b-2c)
7(x+2y -3z)+4(2x-3y-5z)
-3(-2a-4b-c)-6(a-2b-6c)
-5(2x+2y-6z)-(x-7y-3z)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
2(a-4b+c)-5(3a+b-2c)=2a-8b+2c-15a-5b+10c=-13a-13b+12c
7(x+2y-3z)+4(2x-3y-5z)=7x+14y-21z+8x-12y-20z=15x+2y-41y
-3(-2a-4b-c)-6(a-2b-6c)=6a+12b+3c-6a+12b+36c=24b+39c
-5(2x+2y-6z)-(x-7y-3z)=-10x-10y+30z-x+7y+3z= -11x-3y+33z
2(a-4b+c)-5(3a+b-2c) = 2a-2*4b+2c - (5*3a+5b-5*2c)= 2a-8b+2c -15a -5b +10c = -13a -13b +12c
7(x+2y -3z)+4(2x-3y-5z)= 7x+14y-21z +8x -12y-20z=15x+2y-41z
-3(-2a-4b-c)-6(a-2b-6c)= 6a+12b+3c - (6a -12b-36c)= 6a+12b+3c - 6a + 12b + 36c = 24b+39c
-5(2x+2y-6z)-(x-7y-3z)= -10x-10y+30z -x +7y + 3z= -11x+3y+33z