Question

POMOCY Z matematyki!!!!!?????​

Answer 1

8x-2x(3x-1)=2x²+3

8x-6x²+2x=2x²+3

10x-6x²-2x²-3=0

-8x²+10x+3=0 |·(-1)

8x²-10x+3=0

Δ=(-10)²-4·8·3

Δ=100-96

Δ=4

√Δ=√4=2

x₁=(10-2)/(2·8)=8/16=1/2

x₂=(10+2)/(2·8)=12/16=3/4

(2x-4)(2x+4)=(3x-1)²-16

4x²-16=9x²-6x+1-16

4x²-9x²+6x-1=0

-5x-6x+1=0 |·(-1)

5x²-6x+1=0

Δ=(-6)²-4·5·1

Δ=36-20

Δ=16

√Δ=√16=4

x₁=(6-4)/(2·5)=2/10=1/5

x₂=(6+4)/(2·5)=10/10=1

(x²-3x+1)(x+2)=x³-2x-1

x³+2x²-3x²-6x+x+2=x³-2x-1

2x²-3x²-6x+x+2=-2x-1

-x²-5x+2+2x+1=0

-x²-3x+3=0 |·(-1)

x²+3x-3=0

Δ=3²-4·1·(-3)

Δ=9+12

Δ=21

√Δ=√21

x₁=(-3-√21)/(2·1)=-(3+√21)/2

x₂=(-3+√21)/(2·1)=(-3+√21)/2