C17H35COOH + NaOH ---> C17H35COONa + H20
1 mol 1 mol
284g 306g
284g-306g
xkg-3,06kg
x= 284^3,06/306= 28,4 kg kwasu stearynowego
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C17H35COOH + NaOH ---> C17H35COONa + H20
1 mol 1 mol
284g 306g
284g-306g
xkg-3,06kg
x= 284^3,06/306= 28,4 kg kwasu stearynowego
Licze ze pomogłem ^^