Pomocy !!! daje naj !.... Question from @Shizzowany

marokesss

Odpowiedź:

a) u(x)-w(x) = ( $x^{2} -1$ ) - ( $x^{2} -2x+3$ ) = $x^{2} -1$ - $x^{2}$ + 2x - 3 = 2x - 4

u(x)*w(x) = ( $x^{2} -1$ ) * ( $x^{2} -2x+3$ ) = $x^{4}$ - 2 $x^{3}$ + 3 $x^{2}$ - $x^{2}$ + 2x - 3 =

= $x^{4} - 2x^{3}+2x^{2} +2x-3$

b) u(x)-w(x) = (2 $x^{2} -1$ ) - ( $3x^{3} -x^{2}$ ) = 2 $x^{2} -1$ - $3x^{3} +x^{2}$ = - 3 $x^{3}$ +3 $x^{2}$ - 1

u(x)*w(x) = (2 $x^{2} -1$ ) * ( $3x^{3} -x^{2}$ ) = $6x^{5} -2x^{4} -3x^{3} +x^{2}$

Szczegółowe wyjaśnienie:

2 votes Thanks 1

Odpowiedź:

a) u(x) = x² - 1, w(x) = x² - 2x + 3

u(x) - w(x) = x² - 1 - (x² - 2x + 3) = x² - 1 - x² + 2x - 3 = 2x - 4

u(x)•w(x) =

(x² - 1)•(x² - 2x + 3) = x⁴ - x² - 2x³ + 2x + 3x² - 3 = x⁴ - 2x³ + 2x² + 2x - 3

b) u(x) = 2x² - 1, w(x) = 3x³ - x²

u(x) - w(x) = 2x² - 1 - 3x³ + x² = - 3x³ + 3x² - 1

u(x)•w(x) = (2x² - 1)(3x³ - x²) = 6x⁵ - 3x³ - 2x⁴ + x²