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CH3COOH
masa czasteczkowa
mCH3COOH= 12u+1u *3 + 16u*2+1u=60
mC = 12u , mamy 2 wegle wiec 12*2=24u
60 - 100%
24u - x
60x=2400%/:60
x=40% - zawartosc wegla
mO =16u 2*16=32u
60-100%
32u-x
60x=3200%
x=53,3 - zawartosc tlenu
100-53,3-40=6,7%-zawartosc wodoru
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