Pole trójkąta wynosi 12cm2 jego wys. ma 6 cm ile ma podstawa? z obliczeniami !!
P = 12cm^2
h = 6cm
a = ?
P = 1/2 * a * h
12 = 1/2 * a * 6
12 = 3 * a
a = 12 : 3
a = 4cm ------------ odpowiedź
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P = 12cm^2
h = 6cm
a = ?
P = 1/2 * a * h
12 = 1/2 * a * 6
12 = 3 * a
a = 12 : 3
a = 4cm ------------ odpowiedź