Pole trapezu o podstawach 4x i 8y jest równe 4z. Wyznacz wzór na wysokość h tego trapezu.
4z=(4x+8y)h /2 /*2
8z=(4x+8y)h /: (4x+8y)
h=8z/(4x+8y)
h=2z/(x+2y)
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4z=(4x+8y)h /2 /*2
8z=(4x+8y)h /: (4x+8y)
h=8z/(4x+8y)
h=2z/(x+2y)