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H = 5r
V = ?
Pc = 30π
Pc = 2Pp+Pb
30π=2Pp+Pb
30π=2πr²+2πrH
30π=2πr²+2πr*5r
30π=2πr²+10πr²
30π=12πr²//12π
2,5=r²
r=√25*0,1=5√0,1
V=πr²*H=π25*0,1*25√0,1=62,5π√0,1
Objętość tego walca wynosi 62,5π√0,1
Proszę o naj :)