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podstawa 12 pow boczna 36
Pb=?
Pc = 4Pp
Pp = 48/4
Pp = 12 cm^2
Pb = 3* Pp
Pb = 36 cm^2
Pole jednego = 48 cm2 : 4 = 12 cm2,stąd
Pp = 12 cm2,
Pb = 3 * 12 cm2 = 36 cm2
Odp.Pole podstawy tego ostrosłupa równe jest 12 cm2,a jego pole boczne 36 cm2.