Pola figór są równe xkwadrt.Uluz i oblicz odpowiednie rownania:
trójkąt- a=2x-4 h=x+5
prostokąt a=x+10 b=x-2
2x-4>0
2x>4
x>2
P=1/2*(2x-4)(x+5)=(x-2)(x+5)=x2+3x-10
x2+3x-10=x2
3x-10=0
3x=10
x=10/3
2*10/3-4=8/3
10/3+5=25/3
P=1/2*8/3*25/3=11,(11)
x-2>0
P=(x+10)(x-2)=x2+8x-20
x2+8x-20=x2
8x-20=0
8x=20
x=2,5
10+2,5=12,5
2,5-2=0,5
P=12,5*0,5=6,25
Pt=1/2(2x-4)(x+5)=1/2*2(x-2)(x+5)=(x-2)(x+5)
Pt=x^2
x^2+5x-2x-10=x^2
x=3 1/3
Pp=(x+10)(x-2)
Pp=x^2
x^2-2x+10x-20=x^2
x=2 1/2
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2x-4>0
2x>4
x>2
P=1/2*(2x-4)(x+5)=(x-2)(x+5)=x2+3x-10
x2+3x-10=x2
3x-10=0
3x=10
x=10/3
2*10/3-4=8/3
10/3+5=25/3
P=1/2*8/3*25/3=11,(11)
x-2>0
x>2
P=(x+10)(x-2)=x2+8x-20
x2+8x-20=x2
8x-20=0
8x=20
x=2,5
10+2,5=12,5
2,5-2=0,5
P=12,5*0,5=6,25
Pt=1/2(2x-4)(x+5)=1/2*2(x-2)(x+5)=(x-2)(x+5)
Pt=x^2
x^2+5x-2x-10=x^2
3x=10
x=3 1/3
Pp=(x+10)(x-2)
Pp=x^2
x^2-2x+10x-20=x^2
8x=20
x=2 1/2