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5x ramie
3x+5x+5x=26
13x=26
x=26:13
x=2
3x=6
5x=10
10+10+6=26
Odp:Długości boków wynoszą 10cm,10cm i 6cm
a - podstaw
b - ramię
a/b = 3/5
5a = 3b
Obw = a+2b
a+2b = 26
a = 26-2b
a = 26-2b
5a = 3b
a = 26-2b
5(26-2b) = 3b
a = 26-2b
130-10b = 3b
a = 26-2b
-13b = -130 |:(-13)
a = 26-2b
b = 10
a = 26-20
b = 10
a = 6 cm
b = 10 cm << boki trójkąta